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True Discount and Banker's Discount problems tricks in Hindi | fast track formulae for problem solving.

TRUE DISCOUNT AND BANKER'S DISCOUNT TRICKS IN HINDI

TRUE DISCOUNT 1). वास्तविक बट्टा = मिश्रधन - वर्तमान धन
2). यदि ब्याज की दर r% वार्षिक , समय t व वर्तमान धन (pw) है, तो वास्तविक बट्टा = PW×r×t/100
3). यदि r% तथा समय t के बाद देय धन A है, तो तत्काल धन pw = 100×A/(100+r.t)
4). यदि देय धन A पर r% व समय t दिए गए है, तो वास्तविक बट्टा = A.r.t /(100+r.t)
5). यदि किसी निश्चित समय के पश्चात निश्चित वार्षिक दर पर, देय धन पर वास्तविक बट्टा (TD) व समान समय व दर के लिए साधारण ब्याज (SI) हैं, तो देय धन A =      SI × TD/(SI - TD)
6). यदि t समय पश्चात r% वार्षिक दर पर, देय धन पर वास्तविक बट्टा (TD) व साधारण ब्याज (SI) है , तो -  SI - TD = TD×r×t/100
7). t वर्ष बाद r% चक्रवृद्धि दर पर देय धन A का तत्काल धन (PW) = A/(1+r/100)^t   व वास्तविक बट्टा = A - PW
BANKER'S DISCOUNT1). महाजनी बट्टा = शेष समय (समाप्त न हुए समय) के लिए बिल पर ब्याज = बिल की राशि × दर × शेष समय /100
2). महाजनी लाभ = महाजनी बट्टा - वास्तविक बट्टा
3). यदि बिल का मान / अंकित मूल्य A है, समय t व दर r% है, तो महाजनी बट्टा = A×r×t/100
4).…

PROFIT and LOSS for competitive examination, shortcut tricks , fast track formulae

 PROFIT AND LOSS
SOME IMPORTANT SUTRAS

*. Profit = selling price - cost price 
*. Loss = cost price - selling price
*. Cost price = selling price - profit
*. Cost price = selling price + loss
*. Selling price = cost price + profit
*. Selling price = cost price - loss
*. Profit percent = profit × 100/cost price
*. Loss percent = loss ×100/cost price
*. Cost price = SP ×100/(100+P)
*. Cost price = SP ×100/(100 - L)
*. Selling price = CP(100+P)/100
*. Selling price = CP(100-L)/100

*. If a dishonest sellsman sell his goods on CP but he uses fake weight instead of original weight , then the profit percent = 
    100(original weight - fake weight)/fake weight

*. If a dishonest sellsman use x% less weight, but he also sells his goods at y% profit/loss, then net percentage profit/loss = (+-y+x)100/100-x

*. If a sellsman wants to earn b% profit after selling his goods at a% discount , then the sufficient increment in the marked price of the goods is = 100(b+a)/100-a

*. If P sells a object to Q at a% profit/loss , and then Q sells that object to R at b% profit/loss , if R gives A rupees, then the cost price for P is = 
     100×100×A/(100+-a)(100+-b)

*. If a% and b% are two successive profit/loss on any object then the resultant profit/loss = 
  (+-)a + (+-)b + [(+-)a(+-)b/100]

*. A sellsman sells his goods at a% profit , if he sells his goods at R rupees more, then he earn b% profit , then cost price of goods is = 100×R/(b-a)


*. A object is sells at a% profit, if CP and SP both are less by rupees R , then he earn b% more profit, then the CP of the object is = R(a+b)/b

*. If CP of (a) objects is equal to the SP of (b) objects , then the profit percent = 100(a-b)/b

*. If a part of a object is sells at x% profit/loss , b parts at y% profit/loss and c parts at z% profit/loss, this makes total profit/loss of R rupees, then the CP of the objects is = 
       100×R/(ax+by+cz)

*. If A th part of any object is sells with x% loss, if further there will be no loss or profit in whole transaction, for this, the profit percent for the remaining parts of the object should be =
   Ax/(1-A)%

*. The selling price of two objects is Rs X , if one object is sold at r% loss and other object is sold at R% profit- then
**. The CP of the object which are sold at profit =
     x(100+R)/(200-r+R)
**. CP at loss = x(100-r)/(200-r+R)

*. If a object is sold at Rs A with r% profit/loss, then the selling price of the object, if it is sold with R% profit/loss is = A(100+-R)/(100+-r)

*. If a person sold a object with R% profit/loss instead of r% profit/loss and gains the profit of Rs A, then the CP of the object = 100A/R-r

*. If the selling price of two objects are same, one object sold at r% profit and other object sold at r% loss, in this type of transaction always occurred loss, then the loss percent is = r^2/100

*. If CP of x objects is equal to the SP of y objects, if x>y then always be profit then profit percent = 100(x-y)/y , but if x<y then always be loss, then loss percent = 100(y-x)/y

*. A buys a object in Rs x, and sells it to B at r% profit/loss, again B sells it to A at R% profit/loss , then profit of A in this transaction = 
   x(100+-r/100)(1-[100+-R/100])

*. r% profit/loss been if x objects are bought in 1 rupees , then the numbers of objects selling in 1 rupees will be = 1×100/100+-r

*. A person buy y objects in x rupees, and then he sells x objects in y rupees-
If x>y then loss percent = (x^2 - y^2)100/x^2
If x<y , then profit percent = (y^2 - x^2)100/x^2

*. A person sells a object in x% profit/loss , if he bought at y% less/more, and sell at Rs A more/less , then he gains the profit of z% then the CP of the object = 
A[(100+-y/100)(100+-z/100) - (100+-x/100)]

*. After selling a object in x rupees, the gained profit/loss is equal to the cost price of that object then the cost price is = +-50+-10√(25+-x)

*. If a object is bought at the rate of (a) in x rupees, and sells at the rate of (b) in y rupees-then the percentage profit = (ay-bx)100/bx

*. A sellsman cheat while buying object with x% and while selling object he again cheat with x% , then the profit percent = 2x + x^2/100

*. A object with having CP of x rupees, is sold with y% profit , and by another person that object is sold again with z% profit/loss , then the final selling price of that object will be =
     x(100+-y/100)(100+-z/100)

*. A shopkeeper sells his object at cost price with a% profit/loss , but he use b grams instead of c grams  , then profit/loss percent =
       [(c/a)(100+-a) - 100]%

*. The decrease/increases in the usage of the object such that expenditure only increase/decrease by y%, if x% gets increases/decrease in the value of the object is = 
  [1 - (100+-y/100+-x)]100%

*. After selling a object in x rupees , the gained profit is equal to the loss obtained while selling the object in y rupees, then the CP of the object is = x+y/2

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Boat and stream short-tricks in Hindi | Fast track arithmetic formulae for competitive examination.

BOAT AND STREAM (नाव एवं धारा)
1). यदि शांत जल में नाव या तैराक की चाल x किमी/घंटा व धारा की चाल y किमी/घंटा है, तो धारा के अनुकूल नाव अथवा तैराक की चाल = (x+y) किमी/घंटा
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6). शांत जल में किसी नाव की चाल x किमी/घंटा व धारा की चाल y किमी/घंटा है, यदि नाव द्वारा एक स्थान से दूसरे स्थान तक आने व जाने में T समय लगता है, तो दोनो स्थानों के बीच की दूरी = T(x^2 - y^2)/2x km
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A detailed unit conversion table in Hindi.

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